Java by API/java.net/SocketPermission

new SocketPermission(String host, String action)

   <source lang="java">

import java.net.SocketPermission; import java.security.AccessControlException; import java.security.AccessController; public class AccessTest {

 public static void main(String[] a) {
   SocketPermission sp = new SocketPermission("www.jexp.ru", "connect");
   try {
     AccessController.checkPermission(sp);
     System.out.println("Ok to open socket");
   } catch (AccessControlException ace) {
     System.out.println(ace);
   }
 }

}

      </source>