Java Tutorial/Servlet/Forward

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Версия от 17:44, 31 мая 2010; (обсуждение)
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Forward Call from a Servlet

import java.io.IOException;
import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class Main extends HttpServlet {
  protected void service(HttpServletRequest request, HttpServletResponse response)
      throws ServletException, IOException {
    RequestDispatcher dispatcher = request.getRequestDispatcher("/p.jsp");
    dispatcher.forward(request, response);
  }
}





Forward to another location

import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
import java.util.*;
public class MyServlet extends HttpServlet {
  static final String NEW_HOST = "http://www.jexp.ru";
  public void doGet(HttpServletRequest req, HttpServletResponse res)
                               throws ServletException, IOException {
    res.setContentType("text/html");
    PrintWriter out = res.getWriter();
    String newLocation = NEW_HOST;
    res.setHeader("Refresh", "10; URL=" + newLocation);
    out.println("The requested URI has been moved to a different host.<BR>");
    out.println("Its new location is " + newLocation + "<BR>");
    out.println("Your browser will take you there in 10 seconds.");
  }
}