Admin: 1 версия

2010-06-01T05:06:54Z

1 версия

в 17:44, 31 мая 2010

2010-05-31T17:44:27Z

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== Servlet Controller Dispatcher ==



<source lang="java">
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
import java.util.*;
public class MyServlet extends HttpServlet {
public void doGet(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, java.io.IOException {
RequestDispatcher dispatcher = null;
String param = request.getParameter("go");
if (param == null)
throw new
ServletException("Missing parameter in Controller.");
else if (param.equals("weather"))
dispatcher = getServletContext().
getNamedDispatcher("Weather");
else if (param.equals("maps"))
dispatcher = getServletContext().
getNamedDispatcher("Maps");
else
throw new ServletException(
"Improper parameter passed to Controller.");
/*check for a null dispatcher, then
dispatch the request to the correct URL*/
if (dispatcher != null)
dispatcher.forward(request,response);
else
throw new ServletException(
"Controller received a null dispatcher.");
}
}</source>



== Servlet Forwarding Dispatch ==



<source lang="java">
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class MyServlet extends HttpServlet {

public void doGet (HttpServletRequest req, HttpServletResponse res) throws IOException, ServletException
{
ServletContext context = getServletContext();
RequestDispatcher dispatcher = context.getRequestDispatcher("/myServlet");
dispatcher.forward(req,res);
}
}</source>

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Java Tutorial/Servlet/RequestDispatcher - История изменений

Admin: 1 версия

в 17:44, 31 мая 2010