Admin: 1 версия

2010-06-01T06:10:45Z

1 версия

в 18:01, 31 мая 2010

2010-05-31T18:01:43Z

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== Error code ==



<source lang="java">

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class Sender extends HttpServlet {
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, java.io.IOException {
/*
* if the servlet tries to access a resource and finds out that the
* client is not authorized to access it - "401 Unauthorized"
*/
//response.sendError(401,"You are not authorized to view the requested
// component");
/*
* if the servlet tries to access a resource that is forbidden for this
* client and there is no further information on it - "403 Forbidden"
*/
response.sendError(403);
/*
* if the servlet tries to access a resource that is not found given the
* client"s provided URL - "404 Not Found"
*/
//response.sendError(404);
}
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, java.io.IOException {
doPost(request, response);
}
}

</source>



== Generate errors ==



<source lang="java">

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class ErrorGen extends HttpServlet {
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, java.io.IOException {
//check the servlet exception
Throwable throwable = (Throwable) request
.getAttribute("javax.servlet.error.exception");
String servletName = (String) request
.getAttribute("javax.servlet.error.servlet_name");
if (servletName == null)
servletName = "Unknown";
String requestUri = (String) request
.getAttribute("javax.servlet.error.request_uri");
if (requestUri == null)
requestUri = "Unknown";
response.setContentType("text/html");
java.io.PrintWriter out = response.getWriter();
out.println("<html>");
out.println("<head>");
out.println("<title>Error page</title>");
out.println("</head>");
out.println("<body>");
if (throwable == null) {
out.println("<h2>The error information is not available</h2>");
out.println("Please return to the ");
} else {
out.println("<h2>Here is the error information</h2>");
out
.println("The servlet name associated with throwing the exception: "
+ servletName + "<br><br>");
out.println("The type of exception: "
+ throwable.getClass().getName() + "<br><br>");
out.println("The request URI: " + requestUri + "<br><br>");
out.println("The exception message: " + throwable.getMessage());
}
out.println("</body>");
out.println("</html>");
out.close();
}
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, java.io.IOException {
doPost(request, response);
}
}

</source>



== Servlet throws Exceptions ==



<source lang="java">

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class Thrower extends HttpServlet {
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, java.io.IOException {
throw new java.io.IOException("IO thrown");
//response.sendError(403);
}
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, java.io.IOException {
doPost(request, response);
}
}

</source>

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Java/Servlets/Error Exceptions - История изменений

Admin: 1 версия

в 18:01, 31 мая 2010